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Byju's Answer
Standard XII
Mathematics
Basic Inverse Trigonometric Functions
If sin A=si...
Question
If
sin
A
=
sin
B
and
cos
A
=
cos
B
, then
sin
A
−
B
2
=
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Solution
We have
sin
A
=
sin
B
and
cos
A
=
cos
B
or
sin
A
−
sin
B
=
0
and
cos
A
−
cos
B
=
0
or
2
sin
(
A
−
B
2
)
cos
(
A
+
B
2
)
=
0
and
−
2
sin
(
A
−
B
2
)
sin
(
A
+
B
2
)
=
0
or
sin
A
−
B
2
=
0
, which is common for both the equation.
Ans :0
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Q.
If sinA=sinB and cosA=cosB, then
[EAMCET 1994]