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Question

If sinAsinBcosAcosB+1=0, then the value of 1cotAtanB is

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Solution

Given,
sinAsinBcosAcosB+1=0cosAcosBsinAsinB=1cos(A+B)=1sin(A+B)=1cos2(A+B)=0sinAcosB+sinBcosA=0sinAcosB=sinBcosA1=cotAtanB1cotAtanB=2

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