If sin alpha -1 2Tan beta -11 -3Then find sin alpha - beta where alpha and beta are both acute angles

Given : α and β are acute angles. Sin α = 1/2 = Sin (30°) == gt; α = 30° Tan β = 1/√3 = Tan (30°) == gt; β = 30° ∴ Sin (α + β) = Sin (30° + 30°) = Sin( ...

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Mathematics

Standard Values of Trigonometric Ratios

If sin alpha ...

Question

If sin alpha =1\2
Tan beta = 1\√3
Then find sin ( alpha + beta ) where alpha and beta are both acute angles

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Solution

Given : α and β are acute angles.

Sin α = 1/2 = Sin (30°)
==> α = 30°

Tan β = 1/√3 = Tan (30°)
==> β = 30°

∴ Sin (α + β)
= Sin (30° + 30°)
= Sin(60°)
= √3/2
======

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If sin alpha =1\2 Tan beta = 1\√3 Then find sin ( alpha + beta ) where alpha and beta are both acute angles

Given : α and β are acute angles. Sin α = 1/2 = Sin (30°) ==> α = 30° Tan β = 1/√3 = Tan (30°) ==> β = 30° ∴ Sin (α + β) = Sin (30° + 30°) = Sin(60°) = √3/2 ======

If sin alpha =1\2
Tan beta = 1\√3
Then find sin ( alpha + beta ) where alpha and beta are both acute angles

Given : α and β are acute angles.

Sin α = 1/2 = Sin (30°)
==> α = 30°

Tan β = 1/√3 = Tan (30°)
==> β = 30°

∴ Sin (α + β)
= Sin (30° + 30°)
= Sin(60°)
= √3/2
======