If sin -1 and sin- -1-2 where - - -0- - -2- then

The correct options are A tan (α +2β)= √(3) B tan (2α +β)= 1/√(3) Given sin(α+β)=1 , ⇒α+β=π /2 (because α, βϵ [0, π /2]) , Also given ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Complementary Trigonometric Ratios

If sin α+β=...

Question

If $sin (α + β) = 1$ and $sin (α - β) = 1 / 2$ where $α, β ϵ [0, π / 2]$ then

tan (α + 2 β) = - \sqrt{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

tan (2 α + β) = - 1 / \sqrt{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

tan (α + 2 β) = \sqrt{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

tan (α + 2 β) = 1 / \sqrt{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

sin (α + β) = 1

sin (α - β) = \frac{1}{2}

0 \leq α, β \leq \frac{π}{2}

tan (α + 2 β)

tan (2 α + β)

s i n (α + β) = 1

s i n (α - β) = \frac{1}{2},

0 \leq α, β \leq \frac{π}{2},

t a n (α + 2 β)

t a n (2 α + β)

tan α = \frac{1}{7}

sin β = \frac{1}{\sqrt{10}}

0 < α, β < \frac{π}{2}

2 β

cos α = \frac{2 cos β - 1}{2 - cos β}, (0 < α < π, 0 < β < π)

tan \frac{α}{2} cot \frac{β}{2}

tan α = \frac{1}{7}

tan β = \frac{1}{\sqrt{10}}

α + 2 β = \frac{π}{a}

0 < α < \frac{π}{2}

0 < β < \frac{π}{2}

a

Join BYJU'S Learning Program