If sin - - -1- sin - - -1-2- then tan - -2- tan 2- - -

The correct option is A 1 sin(α +β )=1, sin(α β )=1/2 ⇒α +β =π /2,α β =π /6 ⇒α =π3, #160;β =π6 =tan (α +2β ) #160; tan (2α +β ) ...

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Complementary Trigonometric Ratios

If sin α +β...

Question

If $sin (α + β) = 1, sin (α - β) = 1 / 2$ , then $tan (α + 2 β) tan (2 α + β) =$

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Similar questions

sin (α + β) = 1, sin (α - β) = \frac{1}{2},

then tan (α + 2 β) tan (2 α + β)

sin (α + β) = 1

sin (α - β) = \frac{1}{2}

0 \leq α, β \leq \frac{π}{2}

tan (α + 2 β)

tan (2 α + β)

sin (α + β) = 1, sin (α - β) = \frac{1}{2}

α, β \in [0, \frac{π}{2}]

s i n (α + β) = 1

s i n (α - β) = \frac{1}{2},

0 \leq α, β \leq \frac{π}{2},

t a n (α + 2 β)

t a n (2 α + β)

sin (α + β) = 1

sin (α - β) = 1 / 2

α, β ϵ [0, π / 2]

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