If sin-cos90-1-2 and 0- - 90- then find -

The correct option is B 90° nbsp;Given, nbsp;sin α = cos (90° β) = 1/√(2) nbsp; and 0° ≤α, β≤ 90° ⇒ sin α =1/√(2) and cos (90° β) = nbsp;1/√(2) ⇒ ...

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Trigonometric Ratios of Standard Angles

If sinα=cos90...

Question

If $s i n α = c o s (90 ° - β) = \frac{1}{\sqrt{2}}$ and $0 ° \leq α, β \leq 90 °$ , then find $α + β$ .

90°

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60°

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45°

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30°

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Solution

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Similar questions

sin (α + β) = 1, sin (α - β) = \frac{1}{2}

α, β \in [0, \frac{π}{2}]

sin (α + β) = 1

sin (α - β) = \frac{1}{2}

0 \leq α, β \leq \frac{π}{2}

tan (α + 2 β)

tan (2 α + β)

s i n (α + β) = 1

s i n (α - β) = \frac{1}{2},

0 \leq α, β \leq \frac{π}{2},

t a n (α + 2 β)

t a n (2 α + β)

sin (α + β) = 1

s i n (α - β) = \frac{1}{2}

0 \leq α

β \leq \frac{π}{2} t h e n f i n d t h e v a l u e s o f tan (α + 2 β) a n d t a n (2 α + β) .

sin (α + β) = 1

sin (α - β) = 1 / 2

α, β ϵ [0, π / 2]

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