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Question

If sin α & cos α are the roots of the equation ax2+bx+c=0, then

A
a2b2+2ac=0
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B
a2+b2+2ac=0
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C
a2b22ac=0
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D
a2+b22ac=0
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Solution

The correct option is A a2b2+2ac=0
sinα and cosα are the roots of ax2+bx+c=0
sinα+cosα=ba and sinαcosα=ca
(sinα+cosα)2=sin2α+cos2α+2sinαcosα
b2a2=1+2ca
b2=a2+2ac
a2b2+2ac=0
Hence, option A.

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