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Question

If sinα=12, then find the value of 3sinα4sin3α.

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Solution

sinα=12sinαsin30
α=30
3sinα4sin3α=sin3α
=sin3×30
=sin90=1

1215659_1402271_ans_e3b819dd0b8b4f7c83a8e775afd2cd42.jpg

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