If sin- P and tan - Q- then the value of 1- P 2-1- Q 2 is

1/sin^2 α cos^2 α/sin^2 α = 1 ...

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If sinα= P an...

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If sin $α$ = P and tan $α$ = Q, then the value of $\frac{1}{P^{2}} - \frac{1}{Q^{2}}$ is ___

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α

α

\frac{1}{P^{2}} - \frac{1}{Q^{2}}

x^{2} - (α - 2) x - α - 1 = 0

p^{2} + q^{2}

If tan A, tan B are the roots of $x^{2} - P x + Q = 0$ the value of $s i n^{2}$ (A+B)=(where P, Q $ϵ$ R)

\frac{sin A}{sin B} = p, \frac{cos A}{cos B} = q,

tan A = \pm \frac{p}{q} \sqrt{(\frac{1 - q^{2}}{p^{2} - 1})}, tan B = \pm \sqrt{(\frac{1 - q^{2}}{p^{2} - 1})}

p

q

p^{2} + q^{2} = 1

(p + q)

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