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Question

If sinα+sinβ=0=cosα+cosβ, where 0<β<α<2π, then which of the following is correct?

A
α=πβ
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B
α=π+β
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C
α=2πβ
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D
2α=π+2β
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Solution

The correct option is A α=πβ
sinα+sinβ=0sinα=sinβα=πβ or 2πβ

and also
cosα+cosβ=0cosα=cosβα=πβ or π+β

Since, α=πβ is satisfying both equations
then the Answer is A

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