If sin-sin- - a- cos- - cos- - b- then cos- is equal to

The correct option is B b^2 a^2b^2+a^2 cosα + cosβsinα + sinβ = ba ⇒ (cosα + cosβsinα + sinβ)^2 = (ba)^2 ⇒cos^2α + cos^2α + 2 cosαcosβsin^ ...

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AM,GM,HM Inequality

If sinα+sin...

Question

If $sin α + sin β = a, cos α + cos β = b$ , then $cos (α + β)$ is equal to

\frac{a^{2} + b^{2}}{2 a b}

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\frac{2 a b}{a^{2} + b^{2}}

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\frac{b^{2} - a^{2}}{b^{2} + a^{2}}

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\frac{a b}{a^{2} + b^{2}}

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Similar questions

s i n α + s i n β = a

c o s α + c o s β = b,

s i n (α + β) = \frac{2 a b}{a^{2} + b^{2}}

c o s (α + β) = \frac{b^{2} - a^{2}}{b^{2} + a^{2}}

If $s i n α + s i n β = a a n d c o s α + c o s β = b$ , prove that

(i) $s i n (α + β) = \frac{2 a b}{a^{2} + b^{2}}$

(ii) $c o s (α - β) = \frac{a^{2} + b^{2} - 2}{2}$

sin α + sin β = a

cos α + cos β = b

tan \frac{α - β}{2} = \pm \sqrt{\frac{x - a^{2} - b^{2}}{a^{2} + b^{2}}}

x

sin α + sin β = a

cos α + cos β = b

sin α + β = \frac{m a b}{a^{2} + b^{2}}

m

If sin α + sin β = a

cos α + cos β = b

sin (α + β)

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