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Question

If sin α, sin β and cosαare in GP, then roots of the equation x2 + 2xcotβ+1 = 0 are always


A

equal

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B

Real

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C

Imaginary

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D

rational and unequal

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Solution

The correct option is B

Real


sin2β=sinαcosα

cos2β=1sin2α0

Now, the discriminant of the given equation is

4cot2β40

Roots are always real


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