If sin α, sin β and cosαare in GP, then roots of the equation x2 + 2xcotβ+1 = 0 are always
equal
Real
Imaginary
rational and unequal
sin2β=sinαcosα
⇒cos2β=1−sin2α≥0
Now, the discriminant of the given equation is
4cot2β−4≥0
Roots are always real
If sin ∝, sin β and cos∝ are in G.P., then roots of x2 + 2x cot β + 1 = 0 are always :
If sin α, sin β, cos α are in GP, then roots of equation x2 sin β+2x cos β+sin β=0 are