If sin B-1-5sin 2 A - B - then tan A - B -tan t is equal toA- 3-2B- 5-3C- 2-3D- 3-5

The correct option is A sin(2A+B)/sin B=5/1 By componendo and dividendo we shall get tan(A+B)/tanA=3/2 ...

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Sum of Trigonometric Ratios in Terms of Their Product

If sin B=1/5s...

Question

If $sin B = \frac{1}{5} sin (2 A + B),$ then $\frac{t a n (A + B)}{t a n A}$ is equal to

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\frac{1}{5} s i n (2 A + B), t h e n \frac{t a n (A + B)}{t a n A}

sin B = \frac{1}{5} sin (2 A + B),

\frac{t a n (A + B)}{t a n A}

sin B = \frac{1}{5} sin (2 A + B)

tan (A + B) = k tan A

k

In a $Δ$ ABC, if the sides are a = 3, b = 5 and c = 4, then sin B/2 + cos B/2 is equal to

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tan A + tan B + {tan}^{2} A + {tan}^{2} B = 10

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