If sin -4cot -cos -4tan - then -

sin (π4θ)=cos (π4tanθ)π4θ=π2 π4tanθθ=2 tanθ 1=2tanθ tan^2θ tan ^2θ 2tanθ+1=0tanθ=1θ=π4,5π4 ...

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Circular Measurement of Angle

If sin π4cot...

Question

If sin( $\frac{π}{4}$ cot $θ$ )=cos( $\frac{π}{4}$ tan $θ$ ) then $θ$ =?

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If $θ = {sin}^{- 1} x + {cos}^{- 1} x - {tan}^{- 1} x, x \geq 0$ then the smallest interval in which $θ$ lies is

tan [\frac{π}{4} + θ] + tan [\frac{π}{4} - θ] = α

{tan}^{3} [\frac{π}{4} + θ] + {tan}^{3} [\frac{π}{4} - θ] =

m s i n θ = n c o s θ

\frac{t a n θ + c o t θ}{t a n θ - c o t θ} = \frac{n s i n θ + m c o s θ}{n s i n θ - m c o s θ} = \frac{n^{2} + m^{2}}{n^{2} - m^{2}}

y = 1

-

cos θ

x = 1

-

sin θ

\frac{d y}{d x}

θ

=

\frac{π}{4}

If $t a n (\frac{π}{4} + θ) + t a n (\frac{π}{4} - θ) = λ s e c 2 θ$ , then

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