Question

If $\sin ({270}^o-x)=\cos {292}^o$, then find $x$ in $\left({0,360}^o\right).$

Answer 1

Consider the following question.

$\sin ({270}^o-x)=\cos {292}^{o}x\in (0^0,{360}^0)$

$\sin (90\times 3-x)=\cos {292}^0$

$\cos x=\cos {292}^0$

$x={292}^0$

So, $x$ is lies b/w $(0-360)$