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Question

If sin(πcosθ)=cos(πsinθ),then\sin 2\theta) may take value

A
34
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B
34
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C
14
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D
None of these
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Solution

The correct option is C 34
sin(πcosθ)=cos(πsinθ)
cos(π2πcosθ)=cos(πsinθ)
π2πcosθ=πsinθ
π2=π(cosθ+sinθ)
sinθ+cosθ=12 square both sides
sin2θ+cos2θ+2sinθcosθ=14
1+sin2θ=14
sin2θ=34

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