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Question

If sin , sin β and cos are in G.P., then roots of x2 + 2x cot β + 1 = 0 are always :


A

Real

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B

Imaginary

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C

Real and positive

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D

Real and negative

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Solution

The correct option is A

Real


B2 -4AC

Then (2cotβ)2 – 4

4(cot2β-1)

4 tan2β

Here tan2β can’t be negative

Therefore 4tan2β 0

Roots are real


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