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Range of Trigonometric Ratios from 0 to 90 Degrees

If sinθ=13, t...

Question

If $\sin θ = \frac{1}{3}$ , then find the value of 2cot² θ + 2.

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Solution

Given:

We know that,

Therefore,

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Q. Find the value of

Q. The numerical value of

cosec θ [\frac{1 - cos θ}{sin θ} + \frac{sin θ}{1 - cos θ}] - 2 {cot}^{2} θ

\frac{1}{(1 + \sin θ)} + \frac{1}{(1 - \sin θ)} = 2 \sec^{2} θ

\frac{sin θ + cos θ}{sin θ - cos θ} + \frac{sin θ - cos θ}{sin θ + cos θ} = \frac{2}{{sin}^{2} θ - {cos}^{2} θ} = \frac{2 {sec}^{2} θ}{{tan}^{2} θ - 1}

sin θ = \frac{12}{13}

, then the value of

\frac{2 cos θ + 3 tan θ}{sin θ + tan θ sin θ}

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Range of Trigonometric Ratios from 0 to 90 Degrees

Standard X Mathematics

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