If sin - - a - cos - - 1 and tan - - b - cot - - 1- then the value of -a sin - - b equals

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If sin θ : a ...

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If sin θ : a = cos α : 1 and tan θ : b = cot α : 1, then the value of (a sin α) : b equals

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$I f \frac{2 s i n α}{1 + c o s α + s i n α} = y, t h e n \frac{1 - c o s α + s i n α}{1 + s i n α} i s e q u a l t o$

tan θ = \frac{sin α - cos α}{sin α + cos α}; (0 < θ < π) then sin α + cos α a n d sin α - cos α

c o s α, t a n α, c o t α,

s i n α = \frac{5}{13}

\frac{π}{2} < α < π

A = [\begin{matrix} cos α & - sin α sin α & cos α \end{matrix}]

A + A^{'} = I

α

a c o s 2 θ + b s i n 2 θ = c h a s α a n d β

t a n α + t a n β

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