If sin-cos-2 cos 90- find -

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Relation between Trigonometric Ratios

If sinθ+cosθ=...

Question

If sin θ + cos θ = $\sqrt{2} \cos (90 ° - θ)$ , find cot θ.

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If $sin θ + cos θ = \sqrt{2} cos (90^{\circ} - θ)$ , find $cot θ$ ?

sin (90 - θ) + cos θ = \sqrt{2} cos (90 - θ)

0 < θ < 90^{\circ}

cosec θ

\frac{cosec θ + cot θ}{cosec θ - cot θ} = \frac{81}{49}

\frac{cos θ + sin θ}{sin θ - cos θ}

\frac{sin θ - cos θ + 1}{sin θ + cos θ + 1} = \frac{1}{sec θ - tan θ}

{sec}^{2} θ = 1 + {tan}^{2} θ

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