Question

If sin$\theta =-0.6$, the find the quadrant from which the terminal arm making an angle of ${\theta }^o$ passes.

• A. I quadrant
• B. II quadrant
• C. III quadrant
• D. IV quadrant

Answer 1

The correct option is D IV quadrant

Given, $\sin \theta =-0.6$

$⟹\theta ={\sin }^{-1}(-0.6)$

$⟹\theta =-{36.86989765}^o$

Thus, the arm passing through $\theta$ lies in $IV$ quadrant.