If sin theta= 21/29 then evaluate sec thetha/ tan theta - sin theta

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Solution

Given Sinθ = 21/29 = Perpendicular/Hypotaneous

so Base = √[(Hypotaneous)^2 - (Perpendicular)^2]

= √[(29)^2 - (21)^2]

= √(841 - 441)

= √400

= 20

So, Secθ = h/b = 29/20 Tanθ = p/b = 21/20

Secθ 29/20 29/20 29/20 841
So, ---------------- = ----------------- = --------------------- = --------------- = ----- Ans.
(Secθ-Tanθ) 21/20 - 21/29 (609-441)/(20x29) 168/(20x29) 189

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