If sinθ=a,and cosθ=b, then the value of (1−a2)b = __
sin2θ + cos2θ =1
Since, sin2θ = a2 and cos2θ = b2 Therefore, 1-a2 = b2 Therefore on putting sinθ=a and cosθ = b
we get (1−a2)b = b
If sin θ =ab then cos θ = ?
(a) b√b2−a2(b) √b2−a2b(c) a√b2−a2 (d) ba