If sinθ and cosθ are the roots of the equation ax2−bx+c=0, then which one of the following is correct?
A
a2+b2+2ac=0
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B
a2−b2+2ac=0
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C
a2+c2+2ab=0
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D
a2−b2−2ac=0
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Solution
The correct option is Ca2−b2+2ac=0 ax2−bx+c=0 sinθ and cosθ are roots. ∴sinθ+cosθ=ba;sinθcosθ=ca Then (sinθ+cosθ)=b2a2 or sin2θ+cos2θ+2sinθcosθ=b2a2 or 1+2ca=b2a2 or a+2ca=b2a2 or a+2ca×a2=b2 or (a+2c)a=b2 or a2+2ac=b2 or a2−b2+2ac=0