Question

If $sin\Theta =cos60,$ then find the value of $3ta{n}^2\Theta -1$

Answer 1

R.E.F.Image.

$sin\theta =cos{60}^{\circ }$

$\therefore sin\theta =\frac{1}{2}$

$tan\theta =\frac{1}{\sqrt{3}}$

$\therefore 3ta{n}^2\theta -1=3(\frac{1}{\sqrt{3}}{)}^2-1$

$=3\times \frac{1}{3}-1$

$=1-1$

$=0$ Ans