If sin -cos -0 and 0 -2 then - is equal to

The correct option is B π/4 Given, nbsp; sin θ cos θ=0 or nbsp; cosθ=sinθ=cos(π2 θ) or nbsp; θ=(π2 θ)⇒θ=π4 ...

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If sin θ-co...

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If $sin θ - cos θ = 0$ and $0 < θ \leq \frac{π}{2}$ then $θ$ is equal to

\frac{π}{3}

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\frac{π}{4}

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\frac{π}{5}

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\frac{π}{6}

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If $θ = {sin}^{- 1} x + {cos}^{- 1} x - {tan}^{- 1} x, x \geq 0$ then the smallest interval in which $θ$ lies is

\frac{π}{4}

θ

\frac{π}{4}

θ

θ

Which of the following statements are correct?

1 . if sin θ = sin α ⇒ θ = nπ + $(- 1)^{n}$ α where α ∈ [ - $\frac{π}{2}$ , $\frac{π}{2}$ ] n ∈ I

2 . if cos θ = cos α ⇒ 2nπ±α where α ∈ [0,π] n ∈ I

3 . if tan θ = tan α ⇒ θ = nπ + α where α ∈ (- $\frac{π}{2}$ , $\frac{π}{2}$ ) n ∈ I

(θ + \frac{π}{3}) = cos (θ - \frac{π}{6}),

tan θ + \sqrt{3} = 0

sin [\frac{π}{4} cot θ] = cos [\frac{π}{4} tan θ]

θ = n π - \frac{π}{4}, n \in I

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