If sinθ+cosθ=0 and 0<θ<π, then θ
If θ=sin−1x+cos−1x−tan−1x, x≥0 then the smallest interval in which θ lies is
Which of the following statements are correct?
1 . if sin θ = sin α ⇒ θ = nπ + (−1)nα where α ∈ [ - π2 , π2] n ∈ I
2 . if cos θ = cos α ⇒ 2nπ±α where α ∈ [0,π] n ∈ I
3 . if tan θ = tan α ⇒ θ = nπ + α where α ∈ (- π2 , π2 ) n ∈ I