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Question

If sinθ+cosθ=α, then find the values of |sinθcosθ| and sin4θ+cos4θ.

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Solution

Squaring, we get
1+sin2θ=a2sin2θ=a21
|sinθcosθ|=(sinθcosθ)2=1sin2θ=2a2
sin4θ+cos4θ=12sin2θcos2θ=112sin22θ=112(a21)2

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