If sinθ+cosθ=√2cos(90∘−θ), find cotθ ?
If cosθ+sinθ=√2 sin(90∘−θ), then cos θ−sinθ=___
prove that
1+cosec θ+cotθ /1+cosecθ - cotθ = 1+ cosθ = 1+cosθ /sinθ