If sin- - cos- - - 2 sin 90 - - - - show that - - - 2 - 1

sinθ + cosθ = √( 2 )sin( 90 ^ ∘ θ) #160; sinθ+cosθ=√(2)cosθ sinθ=(√(2) 1)cosθ θ=1√(2) 1=√(2)+1(√(2) 1)(√(2)+1)=√(2)+12 1=√(2)+1 ...

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If sinθ + c...

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If $sin θ + cos θ = \sqrt{2} sin (90^{\circ} - θ),$ show that $cot θ = \sqrt{2} + 1$

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If $c o s θ + s i n θ = \sqrt{2} s i n (90^{\circ} - θ),$ then $c o s θ - s i n θ =$ ___

s i n θ + c o s θ = \sqrt{2} s i n (90^{\circ} - θ)

θ .

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