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Question

If sinθ=cosθ, θ being accute, then find the value of 2tanθ+cos2θ.

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Solution

sinθ=cosθ(Given)
To find: 2tanθ+cos2θ
sinθ=cosθ
sinθ=sin(90oθ) (cosθ=sin(90oθ))
θ=90oθ
2θ=90o
θ=45o
2tanθ+cos2θ=2×tan45o+cos245o
=2×1+(12)2
=2+12=4+12=52.

1208737_1399444_ans_3cdb3ed384e34ece9b9fdf69d9ce83a0.jpg

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