If sin- - 12- then find 3 cos- - 4 cos3 -

sinθ =12 ⇒ #160; θ =π6 Now, 3cosθ 4cos^3θ = cos 3θ = cos ( π2 )=0 ...

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Quadratic Formula

If sinθ = 1...

Question

If $sin θ = \frac{1}{2}$ , then find $3 cos θ - 4 {cos}^{3} θ$

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If s i n θ = \frac{1}{2}

θ

then find the value of (3 c o s θ - 4 c o s^{3} θ) .

$If s i n θ = \frac{1}{2}$
and $θ$ is an acute angle, then find the value of $(3 c o s θ - 4 c o s^{3} θ) ?$

sin θ + \sqrt{3} cos θ = \sqrt{2}

θ = \frac{5 π}{m}

m

sin θ + 3 cos θ = \sqrt{2}

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If s i n θ = \frac{1}{2}

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then find the value of (3 c o s θ - 4 c o s^{3} θ) .

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