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Byju's Answer
Standard X
Mathematics
Variation of Trigonometric Ratios from 0 to 90 Degrees
If sinθ =15,...
Question
If
sin
θ
=
1
5
, then, the value of
1
5
cot
2
θ
+
1
5
is equal to:
A
1
125
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B
1
5
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C
25
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D
5
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Solution
The correct option is
C
5
we can write,
cosec
θ
=
5
and
cot
2
θ
=
cosec
2
θ
−
1
⇒
cot
2
θ
=
25
−
1
=
24
Now,
1
5
cot
2
θ
+
1
5
=
24
5
+
1
5
=
5
Therefore, Answer is
5
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Variation of Trigonometric Ratios from 0 to 90 Degrees
Standard X Mathematics
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