Question

If $sin\theta =\frac{3}{5}$ find the values of other trigonometric ratios.

Answer 1

We have , $sin\theta =\frac{3}{5}$

$\therefore cos\theta =\sqrt{1-si{n}^2\theta }\Rightarrow cos\theta =\sqrt{1-\frac{9}{25}}=\sqrt{\frac{16}{25}}=\frac{4}{5}$

$\therefore cosec\theta =\frac{1}{sin\theta }=\frac{5}{3},sec\theta =\frac{1}{cos\theta }=\frac{5}{4}$

$tan\theta =\frac{sin\theta }{cos\theta }=\frac{3/5}{4/5}=\frac{3}{4}$ and $cot\theta =\frac{1}{tan\theta }=\frac{4}{3}$