Question

If $\sin \theta =\frac{3}{5}$, then $\cos \theta +\cot \theta$ is

• A. $\frac{32}{15}$
• B. $\frac{28}{15}$
• C. $\frac{31}{20}$
• D. $\frac{29}{20}$

Answer 1

The correct option is A $\frac{32}{15}$

Consider the $△ABC$

According to the question; $\sin \theta =\frac{3}{5}$

From figure, $\cos \theta =\frac{4}{5}$

$\cot \theta =\frac{4}{3}$

$\therefore \cos \theta +\cot \theta =\frac{4}{5}+\frac{4}{3}=\frac{12+20}{15}=\frac{32}{15}$