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Question

If sinθ=a2b2a2+b2, find the values of other five trignometric ratios.

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Solution

sinθ=a2b2a2+b2
cosθ=(a2b2)2(a2+b2)2(a2+b2)=4a2b2a2+b2=2aba2+b2
tanθ=a2b22ab
secθ=a2+b22ab
cosecθ=a2+b2a2b2
cotθ=2aba2b2

1035125_1057854_ans_4b86b5118e1047739b4bc03c1558cb97.png

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