If sin-24-25 and - lies in the second quadrant then -tan- -

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Range of Trigonometric Ratios from 0 to 90 Degrees

If sinθ=24/...

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If $sin θ = \frac{24}{25}$ and $θ$ lies in the second quadrant then $sec θ + tan θ =$

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If $sin θ = \frac{24}{25}$ and $θ$ lies in the second quadrant, then $sec θ + tan θ =$

sin θ = \frac{7}{25}

θ

sec θ + tan θ

θ

t a n θ = \frac{- 5}{12}

\frac{2 c o s θ}{1 - s i n θ}

sin Θ = \frac{7}{25} a n d Θ

sec Θ + tan Θ

If $θ$ lies in the second quadrant, then the value of $\sqrt{\frac{1 - s i n θ}{1 + s i n θ}}$ + $\sqrt{\frac{1 + s i n θ}{1 - s i n θ}}$ .

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