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Question

If sinθ=12 and tanϕ=13, then the value of θ+ϕ is

A
π6
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B
π
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C
0
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D
π4
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Solution

The correct option is D π4
Given that,
tanθ=12 and tan \phi= \frac{1}{3} \)
Now, tan(θ+ϕ)=tanθ+tanϕ1tanθ.tanϕ
tan(θ+ϕ)=12+13212.13
tan(θ+ϕ)=3+26616=55=1
tan(θ+ϕ)=tanπ4
θ+ϕ=π4

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