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B
π
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C
0
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D
π4
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Solution
The correct option is Dπ4 Given that, tanθ=12 and tan \phi= \frac{1}{3} \) Now, tan(θ+ϕ)=tanθ+tanϕ1−tanθ.tanϕ ⇒tan(θ+ϕ)=12+132−12.13 ⇒tan(θ+ϕ)=3+266−16=55=1 ⇒tan(θ+ϕ)=tanπ4 ∴θ+ϕ=π4