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Question

If sin θ =ab then cos θ = ?

(a) bb2a2(b) b2a2b(c) ab2a2 (d) ba

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Solution

sin θ =ab

cosθ=(1sin2θ)[sin2θ+cos2θ=1]

or, cosθ=(1a2b2)

or, cosθ=(b2a2)b2

or, cosθ=(b2a2)b


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