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Question

If sinθ+sin2θ=1, then find the value of cos4θ+cos2θ1.


A
2
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B
1
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C
0
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-1
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Solution

The correct option is C 0

sinθ+sin2θ=1
1sin2θ=sinθ
cos2θ=sinθ .......(i) [cos2θ+sin2θ=1]

Thus, cos4θ+cos2θ1
=(cos2θ)2(1cos2θ)
=(sinθ)2(sinθ)2 [from (i)]
=0


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