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Question

If sinθ,sinϕ and cosθ are in G.P., then the roots of the equation x2+2xcotϕ+1=0 are always

A
Real
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B
Imaginary
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C
Equal
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D
Greater than 1
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Solution

The correct option is C Real
For G.P. ,
sin2ϕ=sinθcosθ
cosec2ϕ=2sin2θ
cosec2ϕ2=2sin2θ2
cot2ϕ1=2sin2θ2
cot2ϕ1>0
4(cot2ϕ1)>0 or D>0
Hence, equation have always real roots .

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