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Question

If sinx+cosx=y+1y,xϵ[0,π] and y>0, then-

A
x=π/4
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B
x=π2
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C
x=π6
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D
x=3π/4
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Solution

The correct option is A x=π/4
We know that for two positive numbers A.MG.M
y+1y2 ...(i)
1+sin2x=y+1y ...(ii)
From (i) and (ii), we get
sin2x1
sin2x=1
2x=π2
x=π4
Hence, option 'A' is correct.

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