If sin x +cosec x =2, then write the value of sinnx+cosecnx.
sin x +cosec x =2
sinx+1sinx=2
1+sin x=2 sin x
sin x =1
cosec x =1
sinnx+cosecnx=(sinx)n+(cosecx)n
=1+1 =2
If sinx+cosecx=2, then sinnx+cosecnx is equal to [UPSEAT 2002]