Question

If $\sin x=\frac{63}{65},\cos x=\frac{-16}{65}$, the value of $\tan \left(x\right)=$

• A. $\frac{-63}{16}$
• B. $\frac{63}{16}$
• C. $\frac{-33}{56}$
• D. $\frac{33}{56}$

Answer 1

Answer: (A)

$\frac{-63}{16}$

$\tan x=\frac{\sin x}{\cos x}\frac{\frac{63}{65}}{\frac{-16}{65}}=\frac{-63}{16}$