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Question

If sinx+sin2x=1, then the value of cos12x+3cos10x+3cos8x+cos6x−1 is equal to

A
0
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B
1
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C
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D
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Solution

The correct option is C 0
Using sinx+sin2x=1sinx=1sin2x=cos2x
cos12x+3cos10x+3cos8x+cos6x1=sin6x+3sin5x+3sin4x+sin3x1=sin3x(sin3x+3sin2x+3sinx+1)1=sin3x(sinx+1)31=(sin2x+sinx)31=131=11=0

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