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Question

If sinx+sin2x=1, then the value of cos12x+3cos10x+3cos8x+cos6x−2 is equal to

A
0
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B
1
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C
1
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D
2
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Solution

The correct option is C 1
sinx+sin2x=1
sinx+(1cos2x)=1
sinx=cos2x
sin2x=cos4x
Now,
cosx12+3cos10x+3cos8x+cos6x2
=(cos4x+cos2x)32
=(sinx+sin2x)32
=(1)32
=12
=1
Correct option is (C).

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