If $sin x + sin y + sin z = 3$ . Find the value of $cos x + cos y + cos z .$

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Solution

$sin x + sin y + sin z = 3$
$sin x = 1, sin y = 1, sin z = 1$
So, $x = y = z = \frac{π}{2}$
$cosx + cos y + cos z = cos \frac{π}{2} + cos \frac{π}{2} + cos \frac{π}{2} = 0$

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