wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If sin(xy)+yx=x2+y2, find dydx.

A
x3xy2cos(xy)+yx3cos(xy)+xx2y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x3+xy2cos(xy)yx3cos(xy)+x2x2y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x3xy2cos(xy)+yx3cos(xy)x+x2y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2x3xy2cos(xy)+yx3cos(xy)+x2x2y
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2x3xy2cos(xy)+yx3cos(xy)+x2x2y
Differentiating both sides wrt x
cos (xy)[y+xdydx]+1x.dydxyx2=2x+2ydydx
ycos(xy)yx22x=(2yxcos(xy)1x)dydx
dydx=2x3+yx2y(cos(xy))x3cos(xy)+x2x2y

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Theorems in Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon