If sin2A=2sinA. Find A?
Computing the required value:
Given: sin2A=2sinA.
⇒2sinAcosA=2sinA⇒2sinAcosA-1=0⇒sinA=0,cosA=1
We, know that here ,A=0°,A=45°.
Hence, the value of A is 0° and 45°.
In the triangle
(i) If ∠b=600and∠c=500,find∠a.
(ii) If ∠a=1000and∠b=550,find∠c.
(iii) If ∠a=1080and∠c=480,find∠b.