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Question

If sinA-B=12 and cos A+B=12, 0°<A+B90° and A>B then values of A and B are
(a) (60°, 30°)
(b) (60°, 15°)
(c) (45°, 15°)
(d) (60°, 25°)

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Solution

As we know that,
sin30°=12Thus,if sinA-B=12A-B=30° ...1and cos60°=12Thus,if cosA+B=12A+B=60° ...2Solving 1 and 2, we getA=45° and B=15°Hence, the correct optiom is c.

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